the derivative of P=.6P(t) and P(0)=1.....How large is the population after 2 years? and How quickly is the population growing after 2 years?

Question

anonymous · Answer

for the first one I put e^1.2.,...but wrong

unklerhaukus · Answer

$$\lambda P(t)=\frac{\text d P(t)}{\text d t}$$

anonymous · Answer

yes so this makes the equation e^(.6t)
and then wouldnt i just plug in 2 for t to find out how large the population is after 2 years

unklerhaukus · Answer

sounds right to me

anonymous · Answer

so when i put in e^1.2 it says its wrong

anonymous · Answer

or if you dont know what about the second question

unklerhaukus · Answer

so lambda is 0.6

anonymous · Answer

yes

unklerhaukus · Answer

$$P(t)=P_0 e^{\lambda t}$$

$$P(2\text {yr})=P_0 e^{\lambda \cdot 2\text {yr}}$$

$$P(2\text {yr})= e^{0.6 \cdot 2\text {yr}}= e^{1.2}\approx3.320=3\quad (\text{natural number })$$

unklerhaukus · Answer

the population has to be natural number right?