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What is the length of AG in the cube below?
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find the diagonal of base AC first
how do i find that
ABCD is a square, use pythagoras and see if u can find AC
will ac be 12.72
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thats right ! but lets leave it in exact form
so we round it off to 13
\(AC^2 = 9^2 + 9^2\) \(AC^2 = 2 \times 9^2\) \(AC = 9\sqrt{2}\)
we need to still find AG, using this AC
if u see, ACG is again a right angled triangle, we can apply pythagoras and find AG ?
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oh ok i see thanks
\(AG^2 = AC^2 + CG^2\) \(AG^2 = (9\sqrt{2})^2 + 9^2\) \(AG = ? \)
:) yw !
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