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Mathematics 19 Online
OpenStudy (anonymous):

What is the length of AG in the cube below?

OpenStudy (anonymous):

ganeshie8 (ganeshie8):

find the diagonal of base AC first

OpenStudy (anonymous):

how do i find that

ganeshie8 (ganeshie8):

ABCD is a square, use pythagoras and see if u can find AC

OpenStudy (anonymous):

will ac be 12.72

ganeshie8 (ganeshie8):

thats right ! but lets leave it in exact form

OpenStudy (anonymous):

so we round it off to 13

ganeshie8 (ganeshie8):

\(AC^2 = 9^2 + 9^2\) \(AC^2 = 2 \times 9^2\) \(AC = 9\sqrt{2}\)

ganeshie8 (ganeshie8):

we need to still find AG, using this AC

ganeshie8 (ganeshie8):

if u see, ACG is again a right angled triangle, we can apply pythagoras and find AG ?

OpenStudy (anonymous):

oh ok i see thanks

ganeshie8 (ganeshie8):

\(AG^2 = AC^2 + CG^2\) \(AG^2 = (9\sqrt{2})^2 + 9^2\) \(AG = ? \)

ganeshie8 (ganeshie8):

:) yw !

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