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OpenStudy (anonymous):
Find cos θ if sin θ = -5/13 and tan θ > 0.
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myininaya (myininaya):
If sine is negative and tangent is positive, then cosine is ____?____
tangent=sine/cosine=negative/cosine=positive
=>cosine is ___?____
OpenStudy (anonymous):
positive?
myininaya (myininaya):
So negative/positive is positive
No...
OpenStudy (anonymous):
no its negative
myininaya (myininaya):
Right.
You want tangent to be positive not negative
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OpenStudy (anonymous):
positive
myininaya (myininaya):
So you need cosine to be negative in order for tangent to be positive since sine is negative.
myininaya (myininaya):
So we are in the (-,-) quadrant.
OpenStudy (anonymous):
yea
OpenStudy (anonymous):
correct
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myininaya (myininaya):
|dw:1351269639105:dw|
\[\sin( \theta)=-5/13 \text{ is given to you} \]
OpenStudy (anonymous):
so then use pythagorean theorem to fine cosine
myininaya (myininaya):
Find the other side using the Pythagorean thm.
OpenStudy (anonymous):
which would end up being -12/13
myininaya (myininaya):
the other side is 12 is what you are saying
and no i thought you were looking for cosine...
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myininaya (myininaya):
oops I labeled the triangle wrong a little bit.
OpenStudy (anonymous):
i am
myininaya (myininaya):
|dw:1351270002298:dw|
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