Fill in the missing term so that the quadratic equation has a graph that opens up, with a vertex of
(– 3, – 25), and x intercepts at x = -8 and x = 2. (Do not include the negative sign in your answer.)

y = x2 + 6x − ___

Question

Fill in the missing term so that the quadratic equation has a graph that opens up, with a vertex of
(– 3, – 25), and x intercepts at x = -8 and x = 2. (Do not include the negative sign in your answer.) 

y = x2 + 6x −  ___

anonymous · Answer

the missing term there is going to be a constant. lets call it 'c'

We are also given a point on the graph (-3,-25)

We can plug this in and solve for c.

y = x2 + 6x + c
-25 = -3^2 + 6(-3) + c
-25 = 9 + -18 + c
-16 = c

We can check it by using the x intercepts given. y will be zero at these points.
0 = 2^2 + 6(2) - 16
0 = 4 + 12 - 16
0=0

We are correct. Hope this helped

anonymous · Answer

quick note. I have a "+ c" where the equation in your question has a "- c" so the answer they are looking for would be 16