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just looking to get my answer checked! 6e^x/sinx for the derivative i have: -6 g(x)=sinx-cosx/sin^2(x)
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how did the 6 get over there? and what is g(x) and where did e^x go?
i thought they would cancel but, i just looked at my workings and that doesn't make sense because it's sinx(6e^x)-(6e^x)(cosx) g(x) is stated above in my question and i pulled out the 6 because it's a constant
so g(x)=6e^x/sinx ?
yes.
and i need to find the derivative.
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well you have the right numerator so far sinx(6e^x)-(6e^x)(cosx) and the denominator?
sin2x
thats sin squared.
so i can factor out 6e^x on the top.
exactly \[g'(x)=\frac{6e^x\sin x-6e^x\cos x}{\sin^2x}\]
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thank youuuu!
welcome!
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