Question

just looking to get my answer checked!
6e^x/sinx

for the derivative i have: -6 g(x)=sinx-cosx/sin^2(x)

Answer 1

how did the 6 get over there?
and what is g(x)
and where did e^x go?

Answer 2

i thought they would cancel but, i just looked at my workings and that doesn't make sense because it's sinx(6e^x)-(6e^x)(cosx)

g(x) is stated above in my question
and i pulled out the 6 because it's a constant

Answer 3

so g(x)=6e^x/sinx ?

Answer 4

yes.

Answer 5

and i need to find the derivative.

Answer 6

well you have the right numerator so far
sinx(6e^x)-(6e^x)(cosx)

and the denominator?

Answer 7

sin2x

Answer 8

thats sin squared.

Answer 9

so i can factor out 6e^x on the top.

Answer 10

exactly
\[g'(x)=\frac{6e^x\sin x-6e^x\cos x}{\sin^2x}\]

Answer 11

thank youuuu!

Answer 12

welcome!