Question

if anyone can show me how to do these it would be very helpful my mother and I are stumped =.=.........Choose the equation of the line passing through the point (-4, -2) and perpendicular to y = -x + 6. and this one too Choose the equation of the line passing through the point (1, -5) and perpendicular to y = x - 10.

Answer 1

For the first one, perpendicular lines have slopes that are negative inverses of each other, so you can tell from the equation that you were given the slope is -1.

So a line perpendicular to that one would have a slope of 1.

Answer 2

Now that you know the slope do you know what to do?

Answer 3

@Jennylee.lee Hello..0!

Answer 4

Well, if a line is perpendicular to another line, then then the product of their slopes will be -1.

Answer 5

So for the first problem, we have y = -x + 6. The slope of this line is -1, therefore the slope, m, of the other line must be 1.

We need to write the equation of the perpendicular line in the form y = mx + b. Since m = 1, we can write:

y = 1x + b

or simply

y = x + b

Next, we insert the given point (x,y) = (-4,-2) into the equation to get:

-2 = -4 + b

Now we isolate and solve for b:

4 - 2 = b
2 = b

Therefore the equation of the perpendicular line is

y = x + 2

Answer 6

Hopefully, my steps were clear and you can try to do the other one.