Question

The equation of the lines joining the origin to the points of intersection of the line 3x + y = 12 intercepted between the axes of coordinates are

Answer 1

@hartnn

Answer 2

u mean lines or line

Answer 3

Options:
(1) y = 1/ 2 x and y = x ( 2) y = x and y = − x (3) y = 3/ 2 x and y = 6x (4) none of these

Answer 4

ok

Answer 5

i think 4

Answer 6

@experimentX

Answer 7

the required equation is between the points (0,0) and (2,6)
\[y-0=\frac{ 6-0 }{ 2-0 } (x-0)\] giving you y=3x you are done ;)

Answer 8

lol wat is (2,6)

Answer 9

2,6 is the intersection of line 3x+y=12 between the axes

Answer 10

clear? lol

Answer 11

nope..)

Answer 12

@Yahoo! put x=0 and y=0 in the line 3x+y=12 to get those points

Answer 13

i mean find the intercepts of the line dude

Answer 14

3x+y=12

x-inter = 4

y-inter = 12

i got this...)

Answer 15

but did nt get (2,6)

Answer 16

yes and then do your x intercept is (4,0) and y is (0,6) are you kidding me.....man (2,6) is the point of intersection of the line 3x+y=12 THE MID POINT ...are you @Yahoo! lol

Answer 17

i mean you get your intercept

Answer 18

\[x=\frac{ 4+0 }{ 2 }=2 and y=\frac{ 12+0 }{ 2 }=6\] i chose mid point because your question says the point of intersection of line and that is the mid point

Answer 19

@Yahoo! clear?

Answer 20

Yup..Got it..) thxx..

Answer 21

wow, you shocked me lol