Sketch the graph of the given function. g(x) = x3 − 3x, domain [−2, 2] So I have a small question on this problem. I am finding the x-values, so I set the equation=0 and I got x=0,x=+sqrt 3, x=-sqrt 3. I am not sure of the y coordinates to each of these values, any ideas?
what does the function look like
can you see this link? http://www.webassign.net/waplots/9/0/918550fe567c22adff6204a23facdd.gif
well example if x=0 then I have y=g(x)=0^3+3(0)=0 next is x=3 then I have y=3^3+3(3)=27+9=36
sorry thats plus so 27-9=18
I thought you're just supposed to set the whole equation=0 to find the x-intercepts? x3 − 3x=0
then \[x ^{3}-3x= x(x ^{2}-3) \] so x=0 or x\[x ^{2}-3=0\] so x=[\sqrt{3}\]
right
\[x=\pm \sqrt{3}\]
I am just not sure what the y value would be..would I write it as sqrt3,0 or something? or is there a y value? because I tried that and it didnt work
because out of this equation there are 3 x-values, x=0, x=sqrt 3, x=sqrt -3
the question says to graph, is it asking for x cooridants
yup
sorry I already graphed it
there's just multiple parts to the question
and I am just stuck on the coordinates part
what is the other parts?
I mean I got the x's just dont know what the y's would be
Indicate the x- and y-intercepts.
so there are three of them like I said earlier but Idk how I would write it; like (sqrt3,0) (whats the y?)
on x intercepts, the y is 0. so write it as the pair (value, 0)
I tried that it didnt work :/
well (0,0) and (-sqrt3,0) and (sqrt3,0)
yea I did that for some reason its saying its wrong.
please copy the question and let me see
nevermind I got it! I guess this program I am working with just requires a different order. thanks !
Join our real-time social learning platform and learn together with your friends!