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Algebra
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Write a polynomial function f of least degree that has rational coefficients, a leading coefficient of 1, and the zeros 2, -3, -3i
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start with \[(x-2)(x+3)(x+3i)(x-3i)\] and multiply out i would do \[(x+3i)(x-3i)=x^2+9\] first then multiply by the rest
Wait why is there an equal sign right there???
are you asking why \((x+3i)(x-3i)=x^2+9\)
Yes, wouldn't you just multiply them all?
you have to multiply them all, yes but what i meant was i would do that product first because it is the easiest
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\((s+3i)(x-3i)=x^2+3ix-3ix-9i^2=x^2+9\)
Oooohh, I get it! Thanks so much!!
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