how do you solve for x^3 - x^2 +3x+2 ?

Question

anonymous · Answer

solve what?

adunb8 · Answer

solve for x

anonymous · Answer

you do not have an equation
$x$ can be any number

adunb8 · Answer

x^3-x^2+3x+2 = 0 
and solve for what x needs to be

anonymous · Answer

you cant factor it. there is a way to solve for x, which is an extremely complicated process that i would never have been able to do, but the answer can be found here: http://www.wolframalpha.com/input/?i=x%5E3-x%5E2%2B3x%2B2+%3D+0

adunb8 · Answer

hm..... i remember someone doing taking parenthesis both sides like (x^3-x^2) -(3x+2) = 0 or something anyone ring a bell?

anonymous · Answer

that wont work. for that to work, when you factor the 2 individual equations, they must have something in common after you factor them

anonymous · Answer

@ adunb8 what subject are u in?

adunb8 · Answer

this is linear algebra

adunb8 · Answer

/ differential eqn

adunb8 · Answer

um  i dont think so..

adunb8 · Answer

sorry i got the sign wrong. its y'''-y''-3y'+2y=0

adunb8 · Answer

it doesn't say i need to find derivative but yeah if i do it then its 3x^2-2x-3+0

adunb8 · Answer

you got the sign wrong its -3 for the last number but yea that is y'

anonymous · Answer

are you trying to solve it?

anonymous · Answer

so this is the correct prob?
x^3 - x^2 -3x+2 ?

adunb8 · Answer

yea

anonymous · Answer

ok do you know synthetic division?

adunb8 · Answer

i totally forgot =(

anonymous · Answer

doing your synthetic division try +1,-1,2,-2,3,-3

adunb8 · Answer

what i dont understand what +1,-1,2,-2,3,-3 are....

anonymous · Answer

ok if you have x^3 - x^2 -3x+2 =0
  
try 2/ 1  -1  -3     2
                  2     2    -2
        -----------------
           1      1    -1      0     ok that was perpect there  for x=2  that is

y=0= x^3 - x^2 -3x+2
=(x-2)(x^2 +x -1)  here one root of x=2,, now try to find the other two roots

anonymous · Answer

Refer to a solution using  the Mathematica program.