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Mathematics 11 Online
OpenStudy (anonymous):

Help Please!!! *** Fan and medal rewarded*** ***Attachment below***

OpenStudy (anonymous):

OpenStudy (anonymous):

Somebody Help Me!!!!

OpenStudy (anonymous):

Im trying to figure out how to make use of the 'equation' functionality of this site

OpenStudy (anonymous):

ok?

OpenStudy (anonymous):

2x/(y^2-x^2) = 2x/ (y+x) *(y-x) therefore the equation becomes 2x/ (y+x)(y-x) - x/(y-x) = ( 2x- x(y+x) )/ ( (y+x)(y-x) ) =( 2x- xy- x^2) / (y^2- x^2) I hope that makes sense. It was pretty simple, i am not sure if this was what you were looking for. Really sorry for making it exorbitantly late . I was trying to figure out how to use the 'equation' functionality and it was so frustrating

OpenStudy (anonymous):

thanks...

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