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OpenStudy (anonymous):
factor out a 3
OpenStudy (anonymous):
can you take me step by step pn how to do this, I am so confused
OpenStudy (anonymous):
15a(5+2a)
OpenStudy (anonymous):
all of the numbers are divisible by 3 correct
OpenStudy (anonymous):
sorry misread question start by adding like terms
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OpenStudy (anonymous):
all of the numbers are divisible by 15 and they all have a variable of a in them...so, pull out 15a and then you are left with (5+2a). So your answer is 15a(5+2a)
OpenStudy (anonymous):
that is what I got for the number and it advised that I was wrong and I needed to find the gcf first then do the rest, could this be a prime
OpenStudy (anonymous):
sorry class ended and just got back to dorm one sec let me do the problem
OpenStudy (anonymous):
k thanks
OpenStudy (anonymous):
here try this 3 (10 a^2+a+24)
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OpenStudy (anonymous):
wait lost an a there...
OpenStudy (anonymous):
ok ya try factoring out a 3 from 3a+30a^2+72a to get a+10a^2+24a
OpenStudy (anonymous):
a+10a^2+24a=10a^2+25
factor out a 5 to get 5a(2a^2+5)
OpenStudy (anonymous):
factor out a 5a my bad
OpenStudy (anonymous):
it said the answe was 3a(a+6) (a+4). here is another one 3a^3+21a^2+36,
I know that the GCF is 3a but i do not know what to do after that please help