Question

I really need help with this, please help me.
FIND THE VERTEX OF THE PARABOLA!
Y=X^2-6X+7

Answer 1

Hint:

x = -b/(2a)

Answer 2

thankyou, but im not sure where to go with that ^^

Answer 3

Other Hint: Complete the Square.

Answer 4

totally lost :/

Answer 5

The general form of a parabola is

y = ax^2 + bx + c

In this case we have

y = x^2 -6x + 7

a = 1
b = -6
c = 7

To find x, input given values into vertex formula x = -b/(2a):

x = -(-6)/2(1) = 6/2 = 3

The x coordinate of the vertex is 3

To find the y-coordinate, substitute x = 3 into the equation y = x^2 - 6x + 7:
y = (3)^2 - 6(3) + 7
y = 9 - 18 + 7
y = 9 + 7 - 18
y = 16 - 18
y = -2

Therefore the y coordinate of the vertex is -2
Thus the vertex of the parabola is (x,y) = (3,-2)

Answer 6

this was EXTREMELY helpful! thankyou :)