Question

3(6)^x-1=97

Answer 1

is (x-1) all in the exponent?

Answer 2

that is how the problem is in the book

Answer 3

ok. Start by adding 1 to both sides, and dividing both sides by 3

Answer 4

ok

Answer 5

next, take the natural log of both sides, you end up with \[\ln 6^{x}=\ln(98/3)\]

Answer 6

a basic property of logs says that ln(m^n) = n*ln(m)
basically, you can pull out the exponent and put it in front
in this case, you can take the x out of the natural log and put it in front

Answer 7

you end up with x*ln(6) = ln(98/3)
divide both sides by ln(6) to get x

Answer 8

ok