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OpenStudy (anonymous):
10^(x+3)=6^(2x)
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OpenStudy (anonymous):
assuming that you are solving for x introduce log base 10 on both sides
OpenStudy (anonymous):
I get stuck after x+3log10 = 2xlog6
OpenStudy (anonymous):
no you will have
OpenStudy (anonymous):
no you will have \[x + 3 = 2x \log 6 \]
OpenStudy (anonymous):
ok because log10 is 1
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OpenStudy (anonymous):
how to I continue solving for x?
OpenStudy (anonymous):
yep hope you"ll be fine from ther :)
OpenStudy (anonymous):
could you continue a little farther?
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