2 divide by r-2 subtrated from r+3 divide r-1
2 r+3 ----- - ------ = r-2 r-1 this is right ?
the 2 is over r-2 - the r+3 is over the r-1
so than is right ,correct than this you need to calcule ,yes ?
so like a first step you need to calcule the denominator common for (r-2) and (r-1) how many will be ?
(r-2)(r-1)
yes right so than what will be the next step ?
2(r-1) divide by (r-2)(r-1) - (r+3)(r-2) divide by (r-2)(r-1)
yes is right but is more mathematicaly if you write it in this style : 2(r-1) (r+3)(r-2) --------- - ---------- = (r-2)(r-1) (r-2)(r-1) ok ? so the next step ?
i got stuck after that stuck
comen please now this is very easy
2r-2-r^2 -2r +3r -6 ------------------- = (r-2)(r-1)
assume the same terms and than what you will get ?
courage please ,continue it
2r-2-r^2+r-6
not is right 2r canceled out by -2r attention
r *r is r^2
r2+3r-8 / (r-2)(r-1)
so there is -r^2 not plus r^2 yes ?
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