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sin2x+cosx=0
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sin(2x) = 2sin(x)cos(x) After that, you can factor and solve.
Can you do it step by sorry please
*step
You need to be able to do that substitution. sin(2x) + cos(x) = 0 By substitution, is equivalent to 2sin(x)cos(x) + cos(x) = 0 Now you go back to algebra. Factor the expression on the left hand side. We'll come back to trigonometry when you are done factoring and we remember why we are doing that.
I got cosx(2sinx)=0
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Nice try. Remember the Distributive Property 2sin(x)cos(x) + cos(x) = 0 cos(x)(2sin(x) + 1) = 0 You have to believe this.
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