Find all critical numbers for the function f(x)=9x3−27x+4, and then list them (separated by commas) in the box below. If there are no critical numbers, enter None.
@Chlorophyll can you give me a hand?
Critical numbers is obtained when let y' = 0 and y" = 0
all of them, so all i need to do is find the zeros of the derivative?
so for this question 27 (x^2-1) x=1, and x=-1
so then i plug that into original equation and find y?
so 9(1)^3−27(1)+4=-14 and 9(-1)^3−27(-1)+4=22
so (-1,22) and (1,-14) are critical numbers?
how would i find y"?
so again roots of y; are 1 and -1
and root of y'' =0
idk doesnt sound familiar so im guessing not
so what is my answer?
it says that my answer isnt a number its a list of numbers
so try that as an answer?
because that didnt work either
idk just telling you what i was told
Maybe you should link me to the source page or your post is incorrect!
doubt it will work but here it is https://webwork.uwstout.edu/webwork2/math-153-003-fa12/Math153_HW26_Maximum_and_Minimum_Problems/4/?user=relichn0145&effectiveUser=relichn0145&key=SIKe6HI22nYBXJd6enAWqHeHVfPURVgs&displayMode=MathJax&showOldAnswers=1
brb got to go eat
This is not the same problem! ( Yes, late dinner time here, too! )
Try x = 3
im sorry must have been scanning the questions try this https://webwork.uwstout.edu/webwork2/math-153-003-fa12/Math153_HW26_Maximum_and_Minimum_Problems/1/?effectiveUser=relichn0145&displayMode=MathJax&showOldAnswers=1&user=relichn0145&key=QJ0OTtEADUBFSjvnzPRb5WAF80L7Vq0K
i figured it out it was 1,-1
Oh, they means critical NUMBERS are just X values, (without y values ), Hmm!
ya i guess so
yup but that first link that i sent you i cant get it for some reason i got 3 as an answer
You had the answer x= 3?
correct
x=-3 sorry
Mine is x = 3
didnt work either
Yes, your x = -3 is correct!
i guess it was none for some reason
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