Which is the ewuation for the line perpendicular to y= -5/3x + 11 1/3 and conataining p(-2,3)? Hellpp

y- 2 = -3/5(x-3)
y=-5/3x+4 1/5
y = -3/5x + 4 1/5
y= 3/5x + 4 1/5

Question

Which is the ewuation for the line perpendicular to y= -5/3x + 11 1/3 and conataining p(-2,3)? Hellpp

y- 2 = -3/5(x-3)
y=-5/3x+4 1/5
y = -3/5x + 4 1/5
y= 3/5x + 4 1/5

anonymous · Answer

From our last problem, you take the negative reciprocal of the slope of the line in the problem statement.  Can you get that?

anonymous · Answer

i have no idea what u just said

anonymous · Answer

Then you use the point-slope form for the equation of a line.$$y - y _{1} = m(x - x _{1})$$ where "m" is the new slope.

anonymous · Answer

Ok, we'll start with the line in the problem.  It is in the slope-intercept form which is y = mx + b where "m" is the slope.  Just match up the positions. and you will get the slope easily.

anonymous · Answer

would it be -5/3 honestly i have no idea

anonymous · Answer

-5/3 is the slope of the equation in the problem.  You did a good job of identifying it.  So, the slope we want for our new line is 3/5 which is the negative reciprocal, which is switching the numerator and denominator and making it negative.