Brain weight B as a function of body weight W in fish has been modeled by the power function B=.007W2/3, where B and W are measured in grams. A model for body weight as a function of body length L (measured in cm) is W=.12L2.53. If, over 10 million years, the average length of a certain species of fish evolved from 15cm to 20cm at a constant rate, how fast was the species' brain growing when the average length was 18cm? Round your answer to the nearest hundredth.
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OpenStudy (anonymous):
hey did you get all the other webwork questions?
OpenStudy (anonymous):
some of them yes
OpenStudy (anonymous):
which ones did you not get? i'll help you.
OpenStudy (anonymous):
This question and the last one
Are we in the same course ?
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
i have posted these two questions too. working on it
OpenStudy (anonymous):
ok this is very hard for me, last time that I did geometry was 3 years ago and not that hard...
OpenStudy (anonymous):
yeah! tell me about it.
OpenStudy (anonymous):
Im from France, and if you choose economics way in the equivalent of grade 10 here you are not doing geometry anymore
anyway question 9 10 and 14 are hard for me....
OpenStudy (anonymous):
Your name by the way ?
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OpenStudy (anonymous):
did you get 6 and 12? i didnt get them i got 9 i think
OpenStudy (anonymous):
I did 6 but not 12
OpenStudy (anonymous):
#9 = 3819718634
OpenStudy (anonymous):
.3819718634
OpenStudy (anonymous):
theres a decimal
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OpenStudy (anonymous):
do we have the same text ?
it s incorrect for me
OpenStudy (anonymous):
Gravel is being dumped from a conveyor belt at a rate of 30 cubic feet per minute. It forms a pile in the shape of a right circular cone whose base diameter and height are always the same. How fast is the height of the pile increasing when the pile is 10 feet high? Recall that the volume of a right circular cone with height h and radius of the base r is given by V=1/3πr^2h.
OpenStudy (anonymous):
this is mine
OpenStudy (anonymous):
I have 20 cubic feets and 22 feet high
OpenStudy (anonymous):
damn
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13 is the only one that i didnt do
you have the first part ??? What is it ?
OpenStudy (anonymous):
(2q-550/q)
OpenStudy (anonymous):
did you get 14?
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OpenStudy (anonymous):
yep
OpenStudy (anonymous):
but i do think that we dont have the same figures at the beginning :/
OpenStudy (anonymous):
do you have a formula?
OpenStudy (anonymous):
Suppose that water is pouring into a swimming pool in the shape of a right circular cylinder at a constant rate of 5 cubic feet per minute. If the pool has radius 7 feet and height 9 feet, what is the rate of change of the height of the water in the pool when the depth of the water in the pool is 7 feet?
this id my question
OpenStudy (anonymous):
Suppose that water is pouring into a swimming pool in the shape of a right circular cylinder at a constant rate of 5 cubic feet per minute. If the pool has radius 5 feet and height 12 feet, what is the rate of change of the height of the water in the pool when the depth of the water in the pool is 8 feet?
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OpenStudy (anonymous):
never mind i got 14 too
OpenStudy (anonymous):
only 13 2nd part left then right?
OpenStudy (anonymous):
my friend is on it he is going to tell me in a minute
OpenStudy (anonymous):
awesome
OpenStudy (anonymous):
you didn't tell your name
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OpenStudy (anonymous):
neel
OpenStudy (anonymous):
yours?
OpenStudy (anonymous):
stupid me. it must be kessandre!
OpenStudy (anonymous):
nope alexandre :)
OpenStudy (anonymous):
haha
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OpenStudy (anonymous):
who's your teacher
OpenStudy (anonymous):
lindstrom
OpenStudy (anonymous):
maths 104 105
I HAVE THE SOLUTIONS FOR 14
OpenStudy (anonymous):
kessandre is only a nickname
OpenStudy (anonymous):
its for 13sorry
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OpenStudy (anonymous):
WHAT IS IT!!
OpenStudy (anonymous):
my text is Find dRdt when q=5 and dpdt=4.
dRdt=
OpenStudy (anonymous):
sqrt1050 (-2sqrt1050/5)+20
OpenStudy (anonymous):
q=20 and dpdt=3 for me.
OpenStudy (anonymous):
the answer of my buddy was sqrt650 (-sqrt650/5)+20
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OpenStudy (anonymous):
dont know if this is the same for you :/
OpenStudy (anonymous):
nope
OpenStudy (anonymous):
...
OpenStudy (anonymous):
I would not be able to explain I didnt understand everything :(
OpenStudy (anonymous):
thats fine. we still did a lot together.
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OpenStudy (anonymous):
i'll work my way through it
OpenStudy (anonymous):
thats right
i have everything right even for 5
do we have the same text ?