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OpenStudy (anonymous):

Brain weight B as a function of body weight W in fish has been modeled by the power function B=.007W2/3, where B and W are measured in grams. A model for body weight as a function of body length L (measured in cm) is W=.12L2.53. If, over 10 million years, the average length of a certain species of fish evolved from 15cm to 20cm at a constant rate, how fast was the species' brain growing when the average length was 18cm? Round your answer to the nearest hundredth.

OpenStudy (anonymous):

hey did you get all the other webwork questions?

OpenStudy (anonymous):

some of them yes

OpenStudy (anonymous):

which ones did you not get? i'll help you.

OpenStudy (anonymous):

This question and the last one Are we in the same course ?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

i have posted these two questions too. working on it

OpenStudy (anonymous):

ok this is very hard for me, last time that I did geometry was 3 years ago and not that hard...

OpenStudy (anonymous):

yeah! tell me about it.

OpenStudy (anonymous):

Im from France, and if you choose economics way in the equivalent of grade 10 here you are not doing geometry anymore anyway question 9 10 and 14 are hard for me....

OpenStudy (anonymous):

Your name by the way ?

OpenStudy (anonymous):

did you get 6 and 12? i didnt get them i got 9 i think

OpenStudy (anonymous):

I did 6 but not 12

OpenStudy (anonymous):

#9 = 3819718634

OpenStudy (anonymous):

.3819718634

OpenStudy (anonymous):

theres a decimal

OpenStudy (anonymous):

do we have the same text ? it s incorrect for me

OpenStudy (anonymous):

Gravel is being dumped from a conveyor belt at a rate of 30 cubic feet per minute. It forms a pile in the shape of a right circular cone whose base diameter and height are always the same. How fast is the height of the pile increasing when the pile is 10 feet high? Recall that the volume of a right circular cone with height h and radius of the base r is given by V=1/3πr^2h.

OpenStudy (anonymous):

this is mine

OpenStudy (anonymous):

I have 20 cubic feets and 22 feet high

OpenStudy (anonymous):

damn

OpenStudy (anonymous):

no worries...

OpenStudy (anonymous):

Method ?

OpenStudy (anonymous):

i used this

OpenStudy (anonymous):

Thanks

OpenStudy (anonymous):

what did you get for 6 and 12?

OpenStudy (anonymous):

6) (sqrt(65))/8 12) didnt start to di it

OpenStudy (anonymous):

GOT IT GOT GIT IT!!

OpenStudy (anonymous):

#6 that is

OpenStudy (anonymous):

cool :)

OpenStudy (anonymous):

i wish it could be the same for me !!!

OpenStudy (anonymous):

sorry

OpenStudy (anonymous):

did you get 14?

OpenStudy (anonymous):

nope working on it

OpenStudy (anonymous):

me too. i think i almost have it. almost

OpenStudy (anonymous):

me too

OpenStudy (anonymous):

i got 12

OpenStudy (anonymous):

dpes it work ?

OpenStudy (anonymous):

#12 i mean

OpenStudy (anonymous):

yes, for me it does

OpenStudy (anonymous):

post your equation for # 12

OpenStudy (anonymous):

let's see if it's the same

OpenStudy (anonymous):

2x^2+1xp+50p^2=26000.

OpenStudy (anonymous):

-205/11 try it

OpenStudy (anonymous):

and let me know

OpenStudy (anonymous):

you get it right well done i was almost at the end of the computation

OpenStudy (anonymous):

haha

OpenStudy (anonymous):

number 7 ?

OpenStudy (anonymous):

3.020134228 for me

OpenStudy (anonymous):

whats you question? post it

OpenStudy (anonymous):

number 5 (the origin of this conversation actually)

OpenStudy (anonymous):

i didnt get #5

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

did you get #13 second part or 14?

OpenStudy (anonymous):

?

OpenStudy (anonymous):

im working on it for 13 and i m asking a friend for 14

OpenStudy (anonymous):

this can be useful for you maybe http://answers.yahoo.com/question/index?qid=20111013170057AAnKTnO

OpenStudy (anonymous):

i got 10.4 for the brain one but its wrong!

OpenStudy (anonymous):

i got a lot of good answers for which question do you want it ?

OpenStudy (anonymous):

5?

OpenStudy (anonymous):

13 part 2

OpenStudy (anonymous):

0.007 .12^(2/3) 5.06/3 18^(2.06/3) 5/10000000 1000000000

OpenStudy (anonymous):

13 is the only one that i didnt do you have the first part ??? What is it ?

OpenStudy (anonymous):

(2q-550/q)

OpenStudy (anonymous):

did you get 14?

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

but i do think that we dont have the same figures at the beginning :/

OpenStudy (anonymous):

do you have a formula?

OpenStudy (anonymous):

Suppose that water is pouring into a swimming pool in the shape of a right circular cylinder at a constant rate of 5 cubic feet per minute. If the pool has radius 7 feet and height 9 feet, what is the rate of change of the height of the water in the pool when the depth of the water in the pool is 7 feet? this id my question

OpenStudy (anonymous):

Suppose that water is pouring into a swimming pool in the shape of a right circular cylinder at a constant rate of 5 cubic feet per minute. If the pool has radius 5 feet and height 12 feet, what is the rate of change of the height of the water in the pool when the depth of the water in the pool is 8 feet?

OpenStudy (anonymous):

never mind i got 14 too

OpenStudy (anonymous):

only 13 2nd part left then right?

OpenStudy (anonymous):

my friend is on it he is going to tell me in a minute

OpenStudy (anonymous):

awesome

OpenStudy (anonymous):

you didn't tell your name

OpenStudy (anonymous):

neel

OpenStudy (anonymous):

yours?

OpenStudy (anonymous):

stupid me. it must be kessandre!

OpenStudy (anonymous):

nope alexandre :)

OpenStudy (anonymous):

haha

OpenStudy (anonymous):

who's your teacher

OpenStudy (anonymous):

lindstrom

OpenStudy (anonymous):

maths 104 105 I HAVE THE SOLUTIONS FOR 14

OpenStudy (anonymous):

kessandre is only a nickname

OpenStudy (anonymous):

its for 13sorry

OpenStudy (anonymous):

WHAT IS IT!!

OpenStudy (anonymous):

my text is Find dRdt when q=5 and dpdt=4. dRdt=

OpenStudy (anonymous):

sqrt1050 (-2sqrt1050/5)+20

OpenStudy (anonymous):

q=20 and dpdt=3 for me.

OpenStudy (anonymous):

the answer of my buddy was sqrt650 (-sqrt650/5)+20

OpenStudy (anonymous):

dont know if this is the same for you :/

OpenStudy (anonymous):

nope

OpenStudy (anonymous):

...

OpenStudy (anonymous):

I would not be able to explain I didnt understand everything :(

OpenStudy (anonymous):

thats fine. we still did a lot together.

OpenStudy (anonymous):

i'll work my way through it

OpenStudy (anonymous):

thats right i have everything right even for 5 do we have the same text ?

OpenStudy (anonymous):

for 5 we have the same text. yes

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