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find w... 15/w = w/15-w
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\[\frac{ 15 }{ w }=\frac{ w }{ 15 }-w\]
get a common denominator on the right so you can get one fraction
\[ \frac{ 15 }{ w } = \frac{ w }{ 15-w }\]
Sry, I just realized I was using the wrong equation
cross multiply your equation
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225-15w=w^2
set it equal to zero
0 = w^2 + 15w -225
Use the quadratic formula to solve for w
When you have the form\[ax^2+bx+c=0\]Quadratic formula is\[x=-b \pm \frac{ \sqrt{b^2-4ac} }{ 2a }\]
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\[w=-15\pm \frac{ \sqrt{15^2-4*1*-225} }{ 2*1 }\]
sry for the confusion. Do the math above and you should have your answer. There will be 2 answers
one was 9.3, i guess thats the more reasonable answer cause the other was negative
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