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how to factor x^3 - y^3 show steps please
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|dw:1351747219112:dw|
I always thought it was an identity and no steps ....just an answer\[x^3-y^3=(x-y)(x^2+xy+y^2)\]
the identity has to come from somewhere
Choose your god !
You could possibly use algebraic long division with the first factor known to get the second factor.
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choose your god? and im not sure how to go about doing long division on this
we can open \[(x+y)^3=x^3+3xy^2+3x^2y+y^3\] \[(x+y)^3-3xy(x+y)=x^3+y^3\] \[(x+y)((x+y)^2-3xy)=x^3+y^3\] \[(x+y)(x^2+2xy-3xy+y^2)=x^3+y^3\] \[(x+y)(x^2-xy+y^2)=x^3+y^3\]
this is for plus but you can do for -
Very nice work Jonask
alright thanks a lot
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can you do -
x^3-y^3
(x-y)^3
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