Question

How would I figure this out?
The sum of two numbers is 50. The first number is 43 less than twice the second number. Write and solve a system of equations to find the two numbers.

Answer 1

n1 + n2 = 50
(n2-43) + n2 = 50
2n2 - 43 = 50
2n2 =50 +43
n2 = 93/2
n2 = 46.5

and n1 = n2 - 43 = 46.5 - 43 = 3.5

Answer 2

thank you

Answer 3

sorry..., i wrong

n1 + n2 = 50
((2xn2)-43) + n2 = 50
3n2 - 43 = 50
3n2 =50 +43
n3 = 93/2
n3 = 31

and
n1 = (2xn2) - 43 = (2x31) - 43 = 62 - 43 = 19

so n1 = 19 and n2 = 31


this is the real answer @kyrra

Answer 4

its ok i see what you did thanks :)

Answer 5

welcome :)