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Mathematics 9 Online
OpenStudy (anonymous):

Solve the formula for h. (Formula below)

OpenStudy (anonymous):

\[S = 2 \pi rh + 2 \pi r ^{2}\]

OpenStudy (anonymous):

Hey rmaker, I hope I'm not just doing your homework for you! You should treat the other variables like they are numbers, and then solve like you're doing algebra. S = 2pi * r * h + 2pi * r^2 Subtract the term that doesn't have h in it from both sides S - 2pi*r^2 = 2pi * r * h Divide away everything that isn't h from both sides (S - 2pi*r^2)/(2pi * r) = h

OpenStudy (anonymous):

@cholo71796 you are a godsend. (actually you are helping me with my homework. I haven't ate anything since lunch so my brain doesn't work that well.)

OpenStudy (anonymous):

Eating is important! I hope my explanations are making sense though and you're not just writing down my answers!

OpenStudy (anonymous):

not my specialty

OpenStudy (anonymous):

@cholo71796 well, i'm doing both. Thanks for all the help!!

OpenStudy (anonymous):

@cholo71796 sorry, last question. would the simplified form of (S - 2pi*r^2)/(2pi * r) = h be S - pi * r = h?

OpenStudy (anonymous):

No, the simplified form is (S - 2pi*r^2)/(2pi * r) = h

OpenStudy (anonymous):

can't you simplify it even more?

OpenStudy (anonymous):

Not really, you can split it into separate fractions if you'd like S/(2*pi*r) - (2*pi*r^2)/(2*pi*r) which is the same as S/(2*pi*r) - r which is kind of neater but it's not any more simplified

OpenStudy (anonymous):

ok thanks!

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