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Mathematics 16 Online
OpenStudy (vortish):

c=1/6 {pi} p2r

OpenStudy (vortish):

OpenStudy (anonymous):

this one is just straight algebra... doesn't even matter that it's talking about stuff that looks like a circle. c=1/6 {pi} p2r just divide both sides by everything except the "r" (this is like solving for r in a simple equation like C = 10 * r... just divide both sides by 10)

OpenStudy (vortish):

I dont understand are you saying 1/6 divided by 3.14

OpenStudy (anonymous):

\[\frac{ C }{ (\frac{ 1 }{ 6 } {\pi} p ^{2}) } = \frac{ (\frac{ 1 }{ 6 } {\pi} p ^{2}) r }{ (\frac{ 1 }{ 6 } {\pi} p ^{2}) }\]

OpenStudy (anonymous):

you divide both sides by EVERYTHING on the right side except for the "r". This cancels everything but the "r" on the right, so you have "solved" for the "r". So the answer is, r equals that whole expression on the left side... C / ( (1/6) * pi*p^2)

OpenStudy (vortish):

ok

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