Solve for x: −2(x + 3) = −2(x + 1) − 4
what have u tried so far?
|x − 3| = 6 x − 3 = ± 6 x = 3 ± 6
Am really confused.
Are you sure you typed that right? There aren't any solutions for x which satisfy that equation
Sorry, I made a mistake :( x can be any real number because if you multiply out the LHS you get: -2x -6 and if you do the same for the RHS you get: -2x -6, therefore, -2x-6=-2x-6 which is always true
okay so then I work out both sides.
multiply out the brackets on both sides
You get it?
1. -2(x+3) = -2(x+1) - 4 DISTRIBUTE 2. -2x - 6 = -2x - 2 - 4 COMBINE LIKE TERMS 3. -2x - 6 = -2x - 6 As you can see, these are the same equations. X = all real numbers
As you can see karen , the LHS balances with the RHS as Cupcakesforall6 has shown. hence x can be solution of every element from the set of real numbers. {x:x x∈R}
Join our real-time social learning platform and learn together with your friends!