Determine whether the relation is a function. (2 points) b) Explain your answer y= x^5
If there is just one y value for each x value, you have a function instead of just a relation. Is there more than one value of y for x^5?
i guess
try x = 1 , -1 is y different for these values of x?
On the left side, we have as an expression just "y", not anything like y^2, where you would then have to take square roots and get +y and -y. Since there is just "y" on the left, each "x" produces only one "y". Using this and my first post, you should be able to come to the correct conclusion.
I tried 1,-1 its different i get 1,-1
For all "x", you will get only one "y", not multiple "y" values. That is the determining factor in assessing whether you have a relation or a function.
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