Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (anonymous):

Determine whether the relation is a function. (2 points) b) Explain your answer y= x^5

OpenStudy (anonymous):

If there is just one y value for each x value, you have a function instead of just a relation. Is there more than one value of y for x^5?

OpenStudy (anonymous):

i guess

OpenStudy (cwrw238):

try x = 1 , -1 is y different for these values of x?

OpenStudy (anonymous):

On the left side, we have as an expression just "y", not anything like y^2, where you would then have to take square roots and get +y and -y. Since there is just "y" on the left, each "x" produces only one "y". Using this and my first post, you should be able to come to the correct conclusion.

OpenStudy (anonymous):

I tried 1,-1 its different i get 1,-1

OpenStudy (anonymous):

For all "x", you will get only one "y", not multiple "y" values. That is the determining factor in assessing whether you have a relation or a function.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!