Write the equation of a line parallel to y = 3x - 11 and containing the point (2,-3) in y=mx+b format.
are you familiar with point-slope form?
Also, if a line is parallel to another line (let's pretend with a slope of 1), it has the same slope as that line.
therefore both lines have a pretend slope of 1.
I'm not sure, can you show me how to start the problem please?
sure, but do you know point-slope form?
Yes, y-y1 = m(x-x1)
correct. so what's the slope of the original eqn?
3 ?
yes. now plug the new point into point-slope form with the slope from the original eqn, 3.
So, would it be y-y1=3(x-x1) ??
yes. now put in the new ordered pair.
do i substitue x for 2 and x1 for -3 ??
you keep y and x as is. you change x1 and y1 to be the numbers from the new ordered pair: y-(-3)=2(x-(2))
y+3=3x-6 , is that correct, then subtract 3 from both sides?
yep. then you have your answer in m-b form.
Thank you soo much!:)
You're welcome. Enjoy the weekend! Peace out.
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