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A 10ft ladder leans against a wall at an angle theta with the horizontal. The top of the ladder is x feet above the ground. If the bottom of the ladder is pushed toward the wall, find the rate at which x changes with respect to theta when theta=60*
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|dw:1351979408087:dw| like this?
if thats the case, the relationship between theta and x is sin(theta)=x/10 you need to find dx/d(theta) multiply both sides by 10 to get 10sin(theta) = x dx/d(theta) = 10cos(theta) convert 60 degrees to radians plug that number in for theta thats your rate
yes just lke the drawing
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