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OpenStudy (anonymous):
Write 32x5y5 with only one exponent. Use parentheses
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OpenStudy (kropot72):
Hint:\[ax ^{b}y ^{b}=a(xy)^{b}\]
OpenStudy (anonymous):
ok so 32(xy)^10
OpenStudy (kropot72):
Not really. You multiplied the exponent (5) by two when it was not required to do so.
OpenStudy (anonymous):
hmmm
32 = 2^?
OpenStudy (anonymous):
so would u multiplie 5*5 which is 25
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OpenStudy (kropot72):
No. If you read the hint again you will see that the original exponent stays the same value.
OpenStudy (anonymous):
ok im sorry im really bad at math.so if the exponet stays the same then would it be 35(xy)^5
OpenStudy (kropot72):
Yes, you got it. Also as RolyPoly pointed out 32 = 2^5. So you can replace 32 with the number 2 inside the brackets.
OpenStudy (anonymous):
yes thank you very much
OpenStudy (kropot72):
You're welcome :)
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OpenStudy (kropot72):
So did you get the following:
\[(2xy)^{5}\]
OpenStudy (anonymous):
would that be 2*2*2*2*2=32 and would still come out to be 32(xy)^5
OpenStudy (anonymous):
yes
OpenStudy (kropot72):
\[(2xy)^{5}\]
is the most concise answer. However you could put 32 outside the brackets instead of putting 2 inside the brackets if you like.
OpenStudy (anonymous):
\[[ (-1)^5 \(-2)^-3]^2\]
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OpenStudy (anonymous):
i have to Simplify the expression
OpenStudy (anonymous):
-1^5/-2^-6
OpenStudy (anonymous):
(a^x)^y=a^xy
OpenStudy (anonymous):
so how would i get the answer
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