Question

g(x)=ln[(9-x)/(9+x)]

Answer 1

i got -9-x/9-x
this is not right
please help

Answer 2

It's pretty close. BTW, are you solving for x?

Answer 3

??

Answer 4

I'm trying to find g'(x)

Answer 5

Using rules of logs you can split ln[(9-x/9+x)] into ln(9-x)-ln[9+x].
Then using d/dx ln[x]=x'/x you get g(x)=-1/(9-x) - 1/(9+x)
which you can then rearrange to get 18/(x^2 -81)