Question

find the point on the curve y=2x^2-3x+1 where the tangent has the gradient 1.

Answer 1

Find first derivative and set it equal to 1.

Answer 2

6x^2-x=1?

Answer 3

*6x^2-3=1?

Answer 4

Not sure where you're getting the 6..

Answer 5

Is it actually y = 2x^3 + ... ?

Answer 6

oh no wait, i meant 4... i read it wrong

Answer 7

Ok, so your first derivative is y' = 4x-3, right?

Answer 8

yh

Answer 9

(I don't know what "yh" means)

If so, then find x when 4x-3 = 1.

Answer 10

it means yeah as in yes
ok

Answer 11

x=13/4?

Answer 12

Try that again.

Answer 13

sorry, its 1 isnt it

Answer 14

i really dont get how i got the previous answer aha

Answer 15

and y=0?

Answer 16

Yep, that's it. The point is (1,0)

Answer 17

ok thanks for the help:)