I need help..

derivative
y=4sin^(-1)(3x)

I have so far..
y'=d/dx[4arcsin(3x)]
y'=4*d/dx(arcsin(3x))*d/dx(3x)

Question

I need help..

derivative 
y=4sin^(-1)(3x)

I have so far..
y'=d/dx[4arcsin(3x)]
y'=4*d/dx(arcsin(3x))*d/dx(3x)

anonymous · Answer

y = Asin(ωx - φ)

Where:
y = vertical position
A = amplitude
ω = angular fequency
x = horizontal position
φ = phase

Period = T = 1/f = 2π/ω

anonymous · Answer

^wth?

hero · Answer

lol

zepdrix · Answer

Do you know the derivative of arcsine?
Are you allowed to use the shortcut, or do you need to show steps on how you got through it? :D

anonymous · Answer

I don't have to show "exact" steps.. the derivative of arcsine is 1/sqrt(1-x^2)

zepdrix · Answer

Oh ok :) Then it looks like you have it pretty much figured out, only one thing to be careful about though...

anonymous · Answer

but its arcsine of (3x) how do i do that?

zepdrix · Answer

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