Question

A, B, C are angles of a triangle. Show that tan A + tan B + tan C = A tan B tan C

Answer 1

This is exactly how the question is written. However, I suspect that the A must be actually be (tan A) since I don't know of anyway you can "extract" an angle from a tangent (other than arctan, but that would entail additional variables). Either way, I've been trying for a while and can't find an answer,

Answer 2

yes.., I think it's should be tan A + tan B + tan C = (tan A)(tan B) (tan C)

since A, B and C are angles of a triangle, then we have,
A+B+C=180
A+B = 180-C

now, tan(A+B) = tan(180-C)= -tan C

now, use the identity formula of tan(A+B) , then simplify

Answer 3

Thanks alot!

Answer 4

have you got it? :)

Answer 5

yep, thanks for all the help