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OpenStudy (anonymous):
identify the vertex and the axis of symmetry of the graph of the function y = 3(x + 2)2 – 3. (1 point)vertex: (2, –3); axis of symmetry: x = 2 vertex: (–2, –3); axis of symmetry: x = –2 vertex: (2, 3); axis of symmetry: x = 2 vertex: (–2, 3); axis of symmetry: x = –2
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OpenStudy (anonymous):
@ghazi
OpenStudy (ghazi):
have you tried to plot it?
OpenStudy (anonymous):
idk what it even is ghazi
OpenStudy (ghazi):
y=3x+6-3=3x+3 is this clear?
OpenStudy (anonymous):
combine like terms?
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OpenStudy (ghazi):
yes, now lets say we have to find value of y at different values of X
OpenStudy (anonymous):
well y = 3x+3=3x-+3
OpenStudy (ghazi):
y=3x+3, now when x=0,y=3 and when x=-1, y=0 we use this to plot a graph
OpenStudy (ghazi):
wait what is your function it looks like parabola?
OpenStudy (anonymous):
huh?
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OpenStudy (ghazi):
\[y=(3x+2)^2-3\] is this your function?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
no wait the 3 is outside the ()
OpenStudy (ghazi):
\[y=3(x+2)^2-3\] this one
OpenStudy (anonymous):
yes
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