Question

This one's bothering me..
Find equations for two lines through the origin that are tangent to the curve
(x^2) -4x+(y^2)+3=0

Answer 1

Complete the square on the quadratic in x. It's a circle.

Answer 2

tats a equation of circle....

Answer 3

the equation of the line is\[y=+or-\sqrt{1/3}x\]. just by using reduced equation form\[y=mx+b\]. then by solving the system\[\left\{ x ^2-4x+y^2+3=0;y=mx+b \right\}\] and the line containing the origin and verifying the condition of tangency will give the result