Question

Pleaseeeee help me ASAP

f(x)= 1-2(3)^4-2x
1. List the transformations
2. Say where the points (-2, 1/9), (0,1), and (2,9) as well as the horizontal y-asymptote y=o go

Answer 1

@princemartin I can't see your drawing anymore?

Answer 2

Is this right?
\[f(x) = 1-2(3)^{4-2x}\]

Answer 3

Yes!

Answer 4

1) What does
\[f(x) =3^x\] look like?
\[f(x) = -1\cdot 3^x\] look like?
what does
\[f(x) = 3^{-x}\] look like
then
\[f(x) = 3^{-2x}\]
\[f(x)=3^{1-2x}\]
then

Answer 5

1) what does the -2 do in front of the x?
2) what does adding 1 to get 1-2x do?
3) what does multiplying by -2 to do?
4) what does adding 1 do?

Answer 6

I would answer.. but this hw he hasn;t gone over so i really have no idea nor understand the book. I know it has something to do with shifts and shrinks and all that.

Answer 7

Ok. I can't give you answers or the mods hammer me. I will do this for a similar problem for you to learn on and then you can do it yourself, is that ok?

Answer 8

Yeahh thanks!

Answer 9

Ok if you had
\[f(x) = 4^x\]
When x was negative you would have something approaching zero and when positive something approaching really big numbers.

Answer 10

You know that for this (0,1) is a point since
\[4^0 = 1\] and $$4^1=4$$

If you look at $$f(x) = 4^{-x}$$ however you have said all the positive x's are negative and vice versa so you would have:
or a mirror over the y axis