Question

If 40.27 mL of 0.100 M NaOH is required to neutralize 0.314 g of an unknown monoprotic acid, what is the molecular weight of this unknown acid?

Answer 1

The neutralization reaction will require a certain number of moles of sodium hydroxide. This can be calculated from the volume and the molarity thus: 40.27ml of 0.1M equates to 0.00427 moles. So 0.314g of the acid must be equivalent to 0.00427 moles since the acid only has one hydrogen ion (proton) to be neutralized. If you divide the weight of the acid by the number of moles you can find out how much 1 mole weighs, which is the nolecular weight. I hope you get a lot out of using this site, Best wishes,