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Geometry 13 Online
OpenStudy (anonymous):

Calculate the value of x, given line segment FM = 3x and line segment MN = x + 40. A. 13.3 B. 10 C. 40. D. 20

OpenStudy (anonymous):

OpenStudy (ash2326):

@alainabbyboo22 Given that the arcs NM and FM are equal

OpenStudy (ash2326):

so chords will be equal too NM=FM Can you solve it from here ?

OpenStudy (anonymous):

i'm confused on this . what do i need to do ?

OpenStudy (ash2326):

We have the arcs equal as it's indicated in the diagram, isn't it?

OpenStudy (anonymous):

ya

OpenStudy (ash2326):

so the chords ( the straight lines ) NM and FM will be equal NM=FM

OpenStudy (anonymous):

then what do i do ?

OpenStudy (ash2326):

You are given the values of NM and FM in the question. Plug them here : NM=FM

OpenStudy (ash2326):

NM=x+40 FM=3x NM=FM so \[x+40=3x\] Can you solve this @alainabbyboo22 ?

OpenStudy (anonymous):

how do i solve that though ? what do i do ?

OpenStudy (anonymous):

i am sorry if i am irritating you with this but i just don't quite understand this stuff

OpenStudy (ash2326):

No problem. I 'll help you figure this out :)

OpenStudy (anonymous):

thanks so much ! (: i really appreciate it ! thank you for taking your time out of your day to try and help me out on this !

OpenStudy (ash2326):

We are all here to help. You're welcome

OpenStudy (ash2326):

Can you solve this equation for x ? \[x+4=6\]

OpenStudy (anonymous):

would i take the numbers from the answer choices and plug them into x or would i add 4 + 6 ?

OpenStudy (ash2326):

It's just an example, unrelated to the question. Do you know how to solve these type of equations?

OpenStudy (anonymous):

no /:

OpenStudy (ash2326):

Ok. I'll explain you

OpenStudy (ash2326):

Her we have x+4=6 it means that x+4 is equal to 6 x is a variable, we need to find its value which will make this equation true. There is only one value of x which will make this equation true. It's easy to find that :) We need to modify it in such a way that we have x separate and no or no.s separate. \[x+\underline 4=6\] I can see that 4 is on left side. Want to remove it !! So I subtract both sides by 4, it's important to remember that whatever operation I do be it add, subtract, multiply or divide. I have to do on both sides not one side \[x+4-4=6-4\] Now I'll simplify \[x+\cancel 4- \cancel 4=2\] \[x+0=2\] or \[x=2\] Do you get this?

OpenStudy (anonymous):

alright i got that part now !

OpenStudy (ash2326):

good, similarly we have to find the value of x here. We know FM=MN so \[3x=x+40\] here x on the right side is to be removed, what can you do remove x from right side? remember operations on both sides !!

OpenStudy (anonymous):

okay now i'm lost again ..

OpenStudy (ash2326):

I'll give you a hint, subtract both sides by x. what would you get?

OpenStudy (anonymous):

the right side would 38 and the left side would be 1 .

OpenStudy (ash2326):

What did you subtract?

OpenStudy (anonymous):

am i right ?

OpenStudy (anonymous):

i subtracted 40-2 and 3-2

OpenStudy (ash2326):

You made a mistake somewhere. No worries, I'll guide you \[3x=x+40\] subtract both sides by x, because we want to remove x from the right side \[3x-x=x+40-x\] Now what would you get?

OpenStudy (anonymous):

3x=40 ?

OpenStudy (ash2326):

we have 3x-x, on left side or 3x-1x, what would you get on the left side?

OpenStudy (anonymous):

x + 38

OpenStudy (ash2326):

we have \[3x-1x=40\] or \[x(3-1)=40\] What would you get next?

OpenStudy (ash2326):

what's 3-1 ?

OpenStudy (anonymous):

2

OpenStudy (ash2326):

@alainabbyboo22 ?

OpenStudy (anonymous):

i got 2

OpenStudy (anonymous):

where do i go from there now ?

OpenStudy (anonymous):

@ash2326

OpenStudy (ash2326):

so you have \[x \times 2=40\] If you subtract variables, like 4x-2x just subtract 4-2=2 and put the 2 before x but if you have x-x or 9x-9x it'll become 0 do you get this?

OpenStudy (anonymous):

yes i see now . okay what do i do to get my answer ?

OpenStudy (ash2326):

now what do we have?

OpenStudy (anonymous):

2x = 40

OpenStudy (ash2326):

divide both sides by 2, what would you get?

OpenStudy (anonymous):

2 and 20

OpenStudy (ash2326):

\[\frac{2\times x}{2}=\frac{40}{2}\] \[\frac{\cancel 2 \times x}{\cancel 2}=20\] what would you get for x?

OpenStudy (anonymous):

2

OpenStudy (ash2326):

how you would get 2???

OpenStudy (anonymous):

i'm lost .. again .

OpenStudy (anonymous):

would it be 10 ?

OpenStudy (anonymous):

because 20/2

OpenStudy (anonymous):

?

OpenStudy (ash2326):

we have \[2x=40\] divide both sides by 2 only once

OpenStudy (anonymous):

1x = 20

OpenStudy (ash2326):

yeah so x =???

OpenStudy (anonymous):

20 !

OpenStudy (ash2326):

good, did you understand this?

OpenStudy (anonymous):

yes now i do ! thank you very much ! (:

OpenStudy (ash2326):

Welcome and feel free to contact me here, Anytime for help !!

OpenStudy (anonymous):

thanks !! (: have a great day !

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