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Please help with binomial expansion find the 15th term of (a^2+d)^20
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\(\dbinom{20}{14}(a^2)^6b^{14}\) probably easier to compute \(\dbinom{20}{6}\)
thanks for your help so far. to compute this do i compute 20!, divided by 6!?
or would it be 20!/6!(20!-6!)?
then i get .0014?
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