Question

Simplify.

Answer 1

\[\LARGE \sqrt{-10} (11+\sqrt{-5})\]

Answer 2

@jarobins ??? :)

Answer 3

or @jim_thompson5910 ?? :D

Answer 4

First distribute, what do you get?

Answer 5

I don't know. I forgot how to do it.

Answer 6

distributing follows this method

a(b+c) = ab + ac

Answer 7

distribute to get

\[\Large\sqrt{-10} (11+\sqrt{-5})\]

\[\Large 11\sqrt{-10}+\sqrt{-10}\sqrt{-5}\]

\[\Large 11\sqrt{-1*10}+\sqrt{-1*10}\sqrt{-1*5}\]

\[\Large 11*\sqrt{-1}\sqrt{10}+\sqrt{-1}*\sqrt{10}*\sqrt{-1}\sqrt{5}\]

Keep going...

Answer 8

Uh...

Answer 9

Use the fact that \[\Large i = \sqrt{-1}\]

Answer 10

okay so isqrt5 ?

Answer 11

\[\Large\sqrt{-10} (11+\sqrt{-5})\]

\[\Large 11\sqrt{-10}+\sqrt{-10}\sqrt{-5}\]

\[\Large 11\sqrt{-1*10}+\sqrt{-1*10}\sqrt{-1*5}\]

\[\Large 11*\sqrt{-1}\sqrt{10}+\sqrt{-1}*\sqrt{10}*\sqrt{-1}\sqrt{5}\]

\[\Large 11*i\sqrt{10}+i*\sqrt{10}*i\sqrt{5}\]

\[\Large 11*i\sqrt{10}+i^2*\sqrt{10*5}\]

What's next?

Answer 12

I honestly have no clue...

Answer 13

i^2 = ???

Answer 14

?

Answer 15

i = sqrt(-1) agreed?