Question

http://s1274.beta.photobucket.com/user/hmp311/library/

Answer 1

@yummydum

Answer 2

@mark_o.

Answer 3

hi yummy help plz

Answer 4

@JakeV8 hey can u still help real quick?

Answer 5

@jayz657
plz look at both images on the photobucket link above

Answer 6

help me i beg u
ill fan u

Answer 7

for the first pic
your given width = 120yds and legnth= 53 yds

its asking how much yards did they run
so they are asking for perimeter
perimeter = 2length + 2width
perimeter = 2(120) + 2(53)
perimeter = 240 + 106 = 346yards for 1 lap
they ran 30 laps so you multiply that by 30
so 30(346) = 10380 yards is the total dist they ran

Answer 8

hmmm...ok
can you tell me what to put in each square?
abd is this problem no.4?

Answer 9

@mark_o.

Answer 10

that was number 7
figure = rectangle
formula needed = perimeter
measurement to find = yards
what dimension = 120 by 53
key words= 30 laps, how many yards did the team ran
units = yards

Answer 11

oh tnx let me write that real quick

Answer 12

done

Answer 13

number 8
figure = cylinder
formula need = volume of cylinder
measurement to find = cubic centimeter
what dimension = 3 dimension? <- have someone else chekc on this
key words = anything that has a number in it
units = cubic centimeter

Answer 14

writes
thank uuu

Answer 15

number 4
figure = cylinder
formula needed = volume of cylinder
measurement to find = cubic inches
what dimesion= 3 dimension?
key words = anyhting that has numbers with it
units = inches

Answer 16

tnxxx

Answer 17

finally number 5
figure = circle
formula needed = circumference
measurement to find = feet
what dimension = 2 dimension?
key wordds = anything that has a number with it
units = feet

Answer 18

tnx
and six?

Answer 19

six is the last one.

Answer 20

for 6
figure = rectangle
formula needed = area
mmeasurement to find = feet
what dimention = 2d?
key words = anything that has a number with it
units = feet

Answer 21

there you go

Answer 22

tnx!!!!! ur awesome

Answer 23

np glad to help

Answer 24

rewards:fan+medal:)

Answer 25

haha thanks

Answer 26

np:) u deserved both:) n a million more medals:)

Answer 27

oh jayz an unsharpened pencil has a hexagon base with an area 54 mm^2 and length of 200 mm. disregarding the lead, how much wood is needed to create the pencil?

Answer 28

@jayz657

Answer 29

8) the formula for volume in cubic cm, V= pi r^2 h
V=pi(2)^2 (30)= ?

Answer 30

oh its like the rest... key words, units..etc
not actually answering it

Answer 31

but, can u help me find those things in thiis problem?

Answer 32

an unsharpened pencil has a hexagon base with an area 54 mm^2 and length of 200 mm. disregarding the lead, how much wood is needed to create the pencil?

Answer 33

4) given
h=4.5 inch
diameter d=2.5 inch, its radius r=?
r=d/2= 2.5/2 inch
vol V= pi(r)^2 h
V=pi(2.5/2)^2 (4.5)=____? cubic inch

Answer 34

okay

Answer 35

but can you please help me find those specific things in the problem about the pencil?

Answer 36

like thenunits,dimension,key words,etc?

Answer 37

hi jayz

Answer 38

help please?

Answer 39

I beg of you.

Answer 40

5)

circle circumference C=pi d, since we only need half C=pid/2
total perimeter needed P= semicircle C+d = (pi*d/.2) +2.25 = (pi*2.25/2)+2.25 =---?ft.