SECOND ORDER ORDINARY DIFFERENTIAL EQUATION (HELP ME PLEASE)
1.Solve the following differential equation. find the complementary function of this equation.
2y" +4y' +3y = 0

Question

SECOND ORDER ORDINARY DIFFERENTIAL EQUATION (HELP ME PLEASE)
1.Solve the following differential equation. find the complementary function of this equation.
2y" +4y' +3y = 0

anonymous · Answer

firstly you know what is comlementary function

anonymous · Answer

should i tell u directly the sol

anonymous · Answer

yup . help me please :(

anonymous · Answer

i think it is 2nd order linear diffrential equation:)

anonymous · Answer

you want answer no explanation.............

anonymous · Answer

yup. this is second order differential equation. i want answer and explaination, TQ

anonymous · Answer

http://www.wolframalpha.com/input/?i=2y%22+%2B4y%27+%2B3y+%3D+0# see this for solution:)

anonymous · Answer

and for answer wait as i m helping one another person:)

anonymous · Answer

okay :D thank youuuu

anonymous · Answer

now do i need to explain you???????

sirm3d · Answer

do you know the differential operator D and how it is used in solving complementary solution to a differential equation?

anonymous · Answer

do you means (2D^2+4D+3)y=O ?

sirm3d · Answer

good, good. to find the complementary function, you must find the roots of the polynomial in D. what are the roots?

anonymous · Answer

-1 and
 1/$$\sqrt{2}$$

sirm3d · Answer

i think the roots are complex numbers.

anonymous · Answer

yup :D

anonymous · Answer

@DANIEL93  sry i just lost my connection :(

anonymous · Answer

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