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Mathematics 20 Online
OpenStudy (anonymous):

The probability that it rains on any day during the first week of April is 0.2. The probability that it rains three days during the week is given by?

OpenStudy (perl):

so ...

OpenStudy (perl):

lets call the days, 1,2,3,4,5,6,7 . P ( X = 1 or 2 or 3 or 4 or 5... ) = .2 we want P ( x = 1,2,3 or 1,2,4 or 1,2, 5 , etc )

OpenStudy (perl):

i think we can set it up as a binomial problem. the probability of success of raining on any day is .2 . probabiliy of failure is .8 . we want SSSFFFF and combinations thereof

OpenStudy (perl):

P( rains any 3 days ) = 7C3 * .2^3 *.8^4

OpenStudy (perl):

hey fletchnuts

OpenStudy (anonymous):

hey!

OpenStudy (perl):

hi, post away :)

OpenStudy (anonymous):

3. Let U = {a, c, d, f, h, m, p, r, t, w} A = {a, c, f, r, t} B = {a, c, m, t} C = {d, m, p, r, t} Find: a) (A' ∩ B) ∪ (A' ∩ C') b) (A ∩ B ∩ C)' c) (B ∪ C)' ∩ A d) n (A) e) n (A ∪ B)

OpenStudy (perl):

a) , so you understand what complement is , and so forth? union , intersection

OpenStudy (anonymous):

can you explain intersection?

OpenStudy (perl):

you can think of A ' as the universe set minus A , in terms of set theory (removing elements that match )

OpenStudy (perl):

ok so an example A = { 1,2,3} , B = { 1 , 2 , 3,4} A intersect B is { 1,2,3 } , what they have in common

OpenStudy (anonymous):

a' is d,h,m,w?

OpenStudy (anonymous):

ok gotcha

OpenStudy (perl):

Let U = {a, c, d, f, h, m, p, r, t, w} A = {a, c, f, r, t} B = {a, c, m, t} C = {d, m, p, r, t} Find: a) (A' ∩ B) ∪ (A' ∩ C') b) (A ∩ B ∩ C)' c) (B ∪ C)' ∩ A d) n (A) e) n (A ∪ B)

OpenStudy (perl):

Supposing that A = { 1,2,3} , B = { 1 , 2 , 3,4} A union B = { 1 ,2,3,4} A intersect B = {1,2,3} A is a subset of B, but we can about subset later. that just means every element in A is also an element in B

OpenStudy (perl):

U = {a, c, d, f, h, m, p, r, t, w} A = {a, c, f, r, t} B = {a, c, m, t} C = {d, m, p, r, t} A' = { h, m, p, w} B' = { f,h,p,r,w} C' =

OpenStudy (anonymous):

sorry ive been working them out. is a) {h,m,w}?

OpenStudy (anonymous):

c'= a,c,f,h,w?

OpenStudy (perl):

yes

OpenStudy (anonymous):

when you put U = {a, c, d, f, h, m, p, r, t, w} A = {a, c, f, r, t} B = {a, c, m, t} C = {d, m, p, r, t} A' = { h, m, p, w} B' = { f,h,p,r,w} C' = is there supposed to be a "d" in both a' and b'?

OpenStudy (perl):

yes sorry

OpenStudy (anonymous):

alright just making sure i didnt miss something. not tring to call you out. lol

OpenStudy (perl):

when you put U = {a, c, d, f, h, m, p, r, t, w} A = {a, c, f, r, t} B = {a, c, m, t} C = {d, m, p, r, t} A' = {d, h, m, p, w} B' = { d,f,h,p,r,w} C' =

OpenStudy (anonymous):

sweet deal i think i got it now ill let you know if i get stuck!!!!

OpenStudy (perl):

:D

OpenStudy (anonymous):

can you help me with B)?

OpenStudy (anonymous):

b) (A ∩ B ∩ C)'

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