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If cos x = .67, what is sin x?
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Is this with or without a scientific calculator?
use sinx =sqrt(1-cos^2x) =sqrt(1-(.67*.67))
matricked's answer assumes a lot of trigonometry knowledge. How much trigonometry have you done?
\[\cos^2(x) + \sin^2(x) = 1 \\(.67)^2 + sin^2(x) = 1 \\\sin^2(x) = 1 - (.67)^2 \\\sin(x) = \sqrt{1 - (.67)^2} \]
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