Question

x^3-8 x^2+2x+4 %(x^2-4) @HighlyEducated87

Answer 1

i need help please @HighlyEducated87

Answer 2

Just to be sure is there suppose to be a % sign in the problem

Answer 3

x^3-8 x^2+2x+4 (x^2-4)

Answer 4

x^3-8 / x^2+2x+4 (x^2-4) is this the euation sorry

Answer 5

Answer x^3-4x^2+2x-16

Answer 6

x^3-8 / x^2+2x+4 (x^2-4)

Answer 7

@HighlyEducated87 i need help

Answer 8

You want me to explain it

Answer 9

yes

Answer 10

First you write your problem out
Then you multiply 4 times(x^2-4)
That will give you 4x^2-16
So now you rewrite the problem x^3-8x^2+2x+4x^2-16
Now combine all like terms and if a term cannot be combined it stays the same
-8x^2+4x^2 which is -4x^2 becase -8+4= -4
Now you have nothing else to combine
So that leaves you with x^3-4x^2+2x-16
x^3 cannot be combined, 2x cannot be combined and -16 cannot be combined
So your answer is: x^3-4x^2+2x-16

Answer 11

i think x^3-8/x^2+2x+4 divided by (x^2-4)

= (x^3-8) / ((x^2+2x+4)(x^2-4))
= ((x-2)(x^2+2x+4)) / ((x^2+2x+4)(x^2-4)) ... factorise x^3-8
= (x-2) / (x^2-4) ... divide numerator and denominator by x^2+2x+4
= (x-2) / ((x+2)(x-2)) ... factorise x^2 - 4
= 1 / (x+2) ... divide numerator and denominator by x-2

Answer 12

Why didn't you say that?