Question

1.) Solve by factoring: x^2+5x=6

x^2+5x=6
x^2+5x-6=0
(x+6)(x-1)

CHECK
x^2-1x+6x-6
x^2+5x-6

ANSWER: (x+6)(x-1)


what did i do wrong?

Answer 1

(x+6)(x-1) You did nothing wrong.

Answer 2

my teacher said

"Your first problem is not finished. You have to set each factor equal to 0 and solve for x."

Answer 3

oooh nvm i got it lol

Answer 4

Oh. In that case you need to discover when an x would result in an - -- or not.

Answer 5

so i would just put (x+6)=0 x=6
(x-1)=0 x=-1

Answer 6

The opposite. x+6=0 Therefore: x=-6
(x-1)=0 -> x=1

Answer 7

ooooh k but -6+1= -5x not 5x

Answer 8

@malical or @JakeV8

Answer 9

I'm confused at your check. Based on your analysis, 6+6=0.

Answer 10

ok....maybe we should just start the whole problem over lol

Answer 11

i was using FOIL to check

Answer 12

That just seems like a lot of typing. You need to review your answer again.

I got x= -6,1

If you put -6 into the original equation you receive:

36-30=6 which checks out.

Or at 1:

1+5=6 again.

Answer 13

ooh i think your right