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Mathematics
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2x+3y=0 7x=3(2y)+3
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Are you asked to solve the system of equations?
Yes
Okay, then take the second equation: \[7x = 3(2y) + 3\] And multiply the right-hand side out: \[7x = 6y + 3\] Divide both sides by 7: \[x = \frac{6y + 3}{7}\] Substitute this into the first equation: \[2 \times \frac{6y + 3}{7} + 3y = 0\] Multiply both sides by 7: \[2 \times (6y + 3) + 21y = 0\] Multiply out: \[12y + 6 + 21y = 0\] Combine like terms: \[33y + 6 = 0\] Rewrite this equation with just y = on one side to get your y-value, then substitute that back into the second equation to find the x-value.
Ugh thank you so much it makes sense now
You're welcome. They usually turn out cleaner than that... >_<
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