Question

2x+3y=0
7x=3(2y)+3

Answer 1

Are you asked to solve the system of equations?

Answer 2

Yes

Answer 3

Okay, then take the second equation:
\[7x = 3(2y) + 3\]
And multiply the right-hand side out:
\[7x = 6y + 3\]
Divide both sides by 7:
\[x = \frac{6y + 3}{7}\]
Substitute this into the first equation:
\[2 \times \frac{6y + 3}{7} + 3y = 0\]
Multiply both sides by 7:
\[2 \times (6y + 3) + 21y = 0\]
Multiply out:
\[12y + 6 + 21y = 0\]
Combine like terms:
\[33y + 6 = 0\]
Rewrite this equation with just y = on one side to get your y-value, then substitute that back into the second equation to find the x-value.

Answer 4

Ugh thank you so much it makes sense now

Answer 5

You're welcome. They usually turn out cleaner than that... >_<