Mathematics
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OpenStudy (anonymous):
Find g(f(x)) for f(x) = -3x – 6 and G(x)=(-1/2)x+3
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OpenStudy (anonymous):
Simplify this (-1/2)(-3x-6)+3
OpenStudy (anonymous):
Multiply (-3x-6) and (-1/2x+3).
OpenStudy (kira_yamato):
Is \[G(x) = \int\limits g(x) dx\]
OpenStudy (anonymous):
radh thats not right and there is no need for integrals here...
OpenStudy (anonymous):
its just simple substitution
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OpenStudy (anonymous):
How is it not right? you multiply g(x) * f(x)..?
OpenStudy (anonymous):
3/2x+6 ?
OpenStudy (anonymous):
you dont multiply you substitue f(x) into g(x)
OpenStudy (anonymous):
im saying is this the answer?
OpenStudy (anonymous):
Ah, I understand. Sorry.
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OpenStudy (anonymous):
no the answer is 3/2x-15
OpenStudy (anonymous):
oh ok.. thanks!
OpenStudy (anonymous):
What about :
Find f(g(x)) for f(x) = -3x – 6 and g(x)=-1/2x+3
OpenStudy (anonymous):
3/2x+6?
OpenStudy (anonymous):
Oh wow im so sorry i switched then up
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OpenStudy (anonymous):
3/2x+6 is the right answer to the first one and 3/2x-15 is the answer to the second one
OpenStudy (anonymous):
i see!
OpenStudy (kira_yamato):
I suppose the thing is for all Real values of x.
gf(x) = (-1/2)(-3x – 6)+3
gf(x) = 3/2 x + 6
OpenStudy (anonymous):
thanksss
OpenStudy (kira_yamato):
Sorry if I confuse you because I thought G'(x) = g(x) --> saw that in a textbook when I visit Singapore