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give the radius and center for the following equation. (x + 5)2 + (y + 8)2 = 16
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(x – h)^2+ (y – k)^2 = r^2 does that help?
. no not really.
Center at (h, k)
(x – h)^2+ (y – k)^2 = r^2 (x + 5)^2 + (y + 8)^2 = 4^2
this is what i did (x^2+10x+25)+(y^2+16y+64)
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you got it simplified (x – h)^2 + (y – k)^2 = r^2 (x - -5)^2 + (y - -8)^2 = 4^2 r is the radius (h, k) is the center
so what am i suppose to do next?
ooooh nm i got it! :D thanks @surdawi
what did you get?
-5,-8 and 4
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nope center should be written as a point (-5,-8) and r = 4;
thats what i mean.
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